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The angle of elevation of the top of an unfinished tower at a point distant 120 m from its base is 45°. If the elevation of the top at the same point is to be 60°, the tower must be raised to a height :
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- 120 ( √3 + 1 ) m
- 120 ( √3 - 1 ) m
- 10 ( √3 + 1 )
- None of these
Correct Option: B
Let us draw the figure from the given question.
Given :- OB = h + x
In figure , we have
h + x | = | tan 60° | = | √3 | 120 |
h + x | = | √3 (120) ...........( 1 ) |
Also, | h | = | tan 45° = 1 . | 120 |
∴ | h = 120 m |
From eq. ( 1 ) ,
∴ h + x = 120 + x = 120 √3
∴ | x = | 120 ( √3 - 1 ) m . |