According to the question,
2 children = 1 man
∴ (16 children + 24 men) = (8 + 24) men = 32 men
Given M₁ = 32, M₂ = 24, D₁ = 18, D₂ = ?
and W₁ = W₂ = 1
According to the formula, M₁D₁W₂ = M₂D₂W₁

Correct Option: B

According to the question,
2 children = 1 man
∴ (16 children + 24 men) = (8 + 24) men = 32 men
Given M₁ = 32, M₂ = 24, D₁ = 18, D₂ = ?
and W₁ = W₂ = 1
According to the formula, M₁D₁W₂ = M₂D₂W₁
⇒ 32 x 18 x 1 = 24 x D₂ x 1
∴ D₂ = (32 x 18)/24 = 8 x 3 = 24 days

Work done in first in 3 days
= (1/18) + (1/24) + (1/36) = (4 + 3 + 2)/72 = 1/8

Correct Option: C

Work done in first in 3 days
= (1/18) + (1/24) + (1/36) = (4 + 3 + 2)/72 = 1/8

∵ Time taken to complete 1/8 part of work = 3 days
∴ Time taken to complete the whole work = 3 x 8 = 24 days

6 x 12 men = 8 x 18 women = 18 x 10 children
⇒ 12 men = 24 women = 30 children
⇒ 2 men = 4 women = 5 children

Now, 4 men + 12 women + 20 children = 4 men + 6 men + 8 men = 18 m

Correct Option: A

6 x 12 men = 8 x 18 women = 18 x 10 children
⇒ 12 men = 24 women = 30 children
⇒ 2 men = 4 women = 5 children

Now, 4 men + 12 women + 20 children = 4 men + 6 men + 8 men = 18 men
Time to do remaining work in 1 man = (6 x 12 - 18 x 2) = 36 days
∴ Required number of men to finish the work in 1 days = 36

Work done by A in 4 days = 4/20 = 1/5
∴ Remaining work = 1 - 1/5 = 4/5
Let C can working alone complete the work in N days .
According to the question,
18/30 + 18/N = 4/5

Correct Option: D

Work done by A in 4 days = 4/20 = 1/5
∴ Remaining work = 1 - 1/5 = 4/5
Let C can working alone complete the work in N days .
According to the question,
18/30 + 18/N = 4/5
⇒ 18(N + 30) x 5 = 4 x 30 x N
⇒ 90N + 2700 = 120N
⇒ 30N = 2700
∴ N = 90 days

Let B left work after N days from the start.
According to the question,
N/25 + (N + 7)/15 = 1

Correct Option: B

Let B left work after N days from the start.
According to the question,
N/25 + (N + 7)/15 = 1
⇒ (3N + 5N + 35) / 75 = 1
⇒ 8N = 75 - 35
⇒ N = 40/8
∴ N = 5