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16 children and 24 men complete a certain work for 18 days. If each child takes twice the time taken by a man to finish the work in how many days will 24 men finish the same work ?
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- 12 days
- 24 days
- 36 days
- 48 dyas
- None of the above
Correct Option: B
According to the question,
2 children = 1 man
∴ (16 children + 24 men) = (8 + 24) men = 32 men
Given M1 = 32, M2 = 24, D1 = 18, D2 = ?
and W1 = W2 = 1
According to the formula, M1D1W2 = M2D2W1
⇒ 32 x 18 x 1 = 24 x D2 x 1
∴ D2 = (32 x 18)/24 = 8 x 3 = 24 days
