Number System
-  Arrange the following fractions into ascending order.4 ,− 2 ,− 7 , 5 3 9 8 12 
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                        View Hint View Answer Discuss in Forum Decimal equivalents of fractions : 4 = 1.3 3 −2 = −0.2 9 −7 = −0.875 8 5 = 0.42 12 
 Correct Option: ADecimal equivalents of fractions : 4 = 1.3 3 −2 = −0.2 9 −7 = −0.875 8 5 = 0.42 12 
 ∴ – 0.875 < – 0.2 < 0.42 < 1.3i.e., −7 < − 2 < 5 < 4 8 9 12 3 
 
-  A certain number when successively divided by 3, 5 and 8 leaves remainder 1, 2, 3
 respectively. Find the remainders when the same number is divided by reversing the divisors.
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                        View Hint View Answer Discuss in Forum This problem can be solved by determining true or complete remainder and dividing it by reversing the order of divisors. 
 True remainder = d1d2r3 + d1r2 + r1
 Here, d1 = 3, d2 = 5, r1 = 1, r2= 2, r3 = 3
 ∴ True remainder = 3 × 5 × 3 + 3 × 2 + 1= 45 + 6 + 1 = 52
 Now, we divide 52 by 8, 5 and 3 
 Hence, the remainders are 4, 1 and 1.Correct Option: BThis problem can be solved by determining true or complete remainder and dividing it by reversing the order of divisors. 
 True remainder = d1d2r3 + d1r2 + r1
 Here, d1 = 3, d2 = 5, r1 = 1, r2= 2, r3 = 3
 ∴ True remainder = 3 × 5 × 3 + 3 × 2 + 1= 45 + 6 + 1 = 52
 Now, we divide 52 by 8, 5 and 3 
 Hence, the remainders are 4, 1 and 1.
-  What will be the unit’s digit in the product of (2467)153 × (341)72 ?
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                        View Hint View Answer Discuss in Forum The unit’s digit in (2467)153 = The unit’s digit in (7)153 = The 
 unit’s digit in (7)1 = 7
 and the unit’s digit in (341)72 = 1
 Because for any index to 1, the value of unit’s digit will be 1.
 ∴ The unit’s digit in the product of (2467)153 × (341)72 = 7 × 1 = 7Correct Option: CThe unit’s digit in (2467)153 = The unit’s digit in (7)153 = The 
 unit’s digit in (7)1 = 7
 and the unit’s digit in (341)72 = 1
 Because for any index to 1, the value of unit’s digit will be 1.
 ∴ The unit’s digit in the product of (2467)153 × (341)72 = 7 × 1 = 7
-  A candidate in an examination was asked to find 5/14 of a certain number. By mistake he found 5/14 of it. Thus, his answer was 25 more than the correct answer. The number was :
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                        View Hint View Answer Discuss in Forum Let us assume the required number be n. 
 As per given question,⇒ n × 5 − n × 5 = 25 4 14 
 Solve this equation further to get the answer.Correct Option: ALet us assume the required number be n. 
 As per given question,⇒ n × 5 − n × 5 = 25 4 14 ⇒ 5n  1 − 1  = 25 4 14 ⇒ 5n  7 − 2  = 25 ⇒ 5n × 5 = 25 28 28 ⇒ n = 25 × 28 = 28 5 × 5 
-  In an examination, a student was asked to find 3/14 of a certain number, By mistake, he found 3/4 of it. His answer was 150 more than the correct answer. The given number is :
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                        View Hint View Answer Discuss in Forum Let us assume the number is p. 
 According to given question,3 p − 3 p = 150 4 14 ⇒ 21p − 6p = 150 28 
 Solve this equation further to get the answer.
 Correct Option: BLet us assume the number is p. 
 According to given question,3 p − 3 p = 150 4 14 ⇒ 21p − 6p = 150 28 
 ⇒ 15p = 28 × 150⇒ p = 28 × 150 = 280 15 
 
	