Number System
-  The unit’s digit in the product 771 × 663 × 365 is
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                        View Hint View Answer Discuss in Forum 71 = 7, 
 72 = 49,
 73 = 343,
 74 = 2401
 31 = 3,
 32 = 9,
 33 = 27,
 34 = 81
 i.e. the digit at unit’s place gets repeated after power 4. Unit 6 remains same for any power.Correct Option: D71 = 7, 
 72 = 49,
 73 = 343,
 74 = 2401
 31 = 3,
 32 = 9,
 33 = 27,
 34 = 81
 i.e. the digit at unit’s place gets repeated after power 4. Unit 6 remains same for any power.
 ∴ Required unit’s digit
 = Unit’s digit in the product of 73 × 6 × 1 = 4
-  The unit digit in the product (122)173 is
- 
                        View Hint View Answer Discuss in Forum 21 = 2 
 22 = 4
 23 = 8
 24 = 16
 25 = 32
 Now As we know that,
 Unit place of 21 = 2
 Unit place of 22 = 4
 Unit place of 23 = 8
 Unit place of 24 = 6
 Unit place of 25 = 2
 i.e. 2 repeats itself after the index 4.Correct Option: A21 = 2 
 22 = 4
 23 = 8
 24 = 16
 25 = 32
 Now As we know that,
 Unit place of 21 = 2
 Unit place of 22 = 4
 Unit place of 23 = 8
 Unit place of 24 = 6
 Unit place of 25 = 2
 i.e. 2 repeats itself after the index 4.
 ∴ Unit digit in the product of (122)173
 = Unit digit in (122)1 = 2
 (1 = remainder when 173 is divided by 4).
-  One’s digit of the number (22)23 is
- 
                        View Hint View Answer Discuss in Forum Unit’s digit in the expansion of (22)23 = Unit’s digit in the expansion of (2)23 
 21 = 2
 22 = 4
 23 = 8
 24 = 16
 25 = 32Correct Option: CUnit’s digit in the expansion of (22)23 = Unit’s digit in the expansion of (2)23 
 21 = 2
 22 = 4
 23 = 8
 24 = 16
 25 = 32
 Now As we know that,
 Unit place of 21 = 2
 Unit place of 22 = 4
 Unit place of 23 = 8
 Unit place of 24 = 6
 Unit place of 25 = 2
 i.e. 2 repeats itself after the index 4.
 On dividing 23 by 4, remainder = 3
 ∴ Unit’s digit in (2)23 = Unit’s digit in (2)3 = 8
-  The last digit of 340 is
- 
                        View Hint View Answer Discuss in Forum 31 = 3; 
 32 = 9;
 33 = 27;
 34 = 81;
 35 = 343 ; ...........................................
 We can write 340 as below,
 340 = 34 x 34 x ........ 10 times
 Unit place digit for 340 = Unit place Digit of 34 x Unit place Digit of 34 x.......... 10 timesCorrect Option: A31 = 3; 
 32 = 9;
 33 = 27;
 34 = 81;
 35 = 343 ; ...........................................
 We can write 340 as below,
 340 = 34 x 34 x ........ 10 times
 Unit place digit for 340 = Unit place Digit of 34 x Unit place Digit of 34 x.......... 10 times
 Unit place digit for 340 = 1 x 1 x............. 10 times
 ∴ Unit’s digit in 340 = 1
-  Unit digit in (264)102 + (264)103 is :
- 
                        View Hint View Answer Discuss in Forum Unit digit in (264)4 4 × 4 × 4 × 4 is 6 
 ∴ Unit digit in (264)100 is also 6.
 Now, (264)102 = (264)100 × (264)2
 = (Unit digit 6) × (Unit digit 6) = 36
 ∴ Unit digit is 6Correct Option: AUnit digit in (264)4 4 × 4 × 4 × 4 is 6 
 ∴ Unit digit in (264)100 is also 6.
 Now, (264)102 = (264)100 × (264)2
 = (Unit digit 6) × (Unit digit 6) = 36
 ∴ Unit digit is 6
 Similarly 
 Therefore, the unit digit in (264)102 + (264)103 is 6 + 4 = 10 i.e. 0.
 
	