Number System
- The least number among
4 , √ 9 , 0.45 and (0.8)2 is 9 49
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Decimal equivalents :
4 = 0.4; √ 9 = 3 = 0.43 9 49 7
0.45, (0.8)2 = 0.64Correct Option: B
Decimal equivalents :
4 = 0.4; √ 9 = 3 = 0.43 9 49 7
0.45, (0.8)2 = 0.64
∴ Least number = 0.43= √ 9 49
- The largest among the numbers
(0.1)2, √0.0121, 0.12 and √0.0004 is
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(0.1)2 = 0.01
√0.0121 = √0.11 × 0.11 = 0.11
√0.0004 = 0.02Correct Option: C
(0.1)2 = 0.01
√0.0121 = √0.11 × 0.11 = 0.11
√0.0004 = 0.02
After arranging the given numbers in increasing order, we will get
⇒0.01 < 0.02 < 0.11 < 0.12
So clearly 0.12 is the biggest fraction in the given question.
- When 335 is added to 5A7, the result is 8B2. 8B2 is divisible by 3. What is the largest possible value of A ?
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5 A 7
3 3 5 8 B 2
⇒ A → 0, 1, 2, 3, 4, 5
& B → 4, 5, 6, 7, 8, 9Correct Option: D
5 A 7
3 3 5 8 B 2
⇒ A → 0, 1, 2, 3, 4, 5
and B → 4, 5, 6, 7, 8, 9
8B2 is exactly divisible by 3.
∴ 8 + B + 2 = 10 + B = multiple of 3
∴ B = 5 or 8
⇒ A = 1 or 4
- If a number is as much greater than 31 as it is less than 75, then the number is
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Let us assume that number is P.
Then according to question, Number is as much greater than 31 as it is less than 75,
P – 31 = 75 – PCorrect Option: D
Let us assume that number is P.
Then according to question, Number is as much greater than 31 as it is less than 75,
P – 31 = 75 – P
⇒ 2P = 75 + 31 = 106
⇒ P = 53
- The greatest number among
0.7 + √0.16, 1.02 − 0.6 , 1.2 × 0.83 and √1.44 is : 24
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Solve the given equation one by one.
0.7 + √0.16 = 0.7 + 0.4 = 1.1Correct Option: B
Solve the given equation one by one.
First equation; 0.7 + √0.16 = 0.7 + 0.4 = 1.1Second equation; 1.02 − 0.6 24
= 1.02 – 0.025
= 0.995
Third equation; 1.2 × 0.83 = 0.996
Fourth equation; √1.44 = 1.2
Hence, the greatest number
= √1.44
