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  1. If cosθ + secθ = √3 , then the value of (cos3θ + sec3θ) is :
    1. 1
    2. 1
      2

    3. 0
    4. 2
Correct Option: C

a3 + b3 = (a + b)3 - 3ab(a + b)
∴ cos3θ + sec3θ = (cosθ + secθ)3 - 3cosθ . secθ(cosθ + secθ)
cos3θ + sec3θ = ( √3 )3 - 3 × √3
{ ∵ cosθ + secθ = √3 }
cos3θ + sec3θ = 3√3 - 3√3 = 0



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