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					 A vertical pole AB is standing at the centre B of a square PQRS.If PR subtends an angle of 90° at the top, A of the pole, then the angle subtended by a side of the square at A is :
- 
                        -  30° 
 
-  45°
 
-  60°
 
- None of these
 
-  30° 
Correct Option: C

PA = PR
∠APB = ∠ARB = 45°
If PR = √2x :
| PB = | ||
| √2 | 
From triangle APB ,
| tan45° = | ⇒ AB = PB = | ||
| PB | √2 | 
∴ PA = √( x2 / 2 ) + ( x2 / 2 ) = √x2 = x
∴ QA = PQ = PA = x
∴ ∠PAQ = 60°
 
	