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  1. If
    p2
    +
    q2
    = 1 , then the value of (p6 + q6) is
    q2p2

    1. 0
    2. 1
    3. 2
    4. 3
Correct Option: A

p2
+
q2
= 1
q2p2

p4 + q4
= 1
p2q2

⇒ p4 + q4 = p2q2
⇒ p4 + q4 - p2q2 = 0 ...... (i)
∴ p6 + q6 = (p2)3 + (q2)3
p6 + q6 = (p2 + q2)(p4 + q4 - p2q2)
[ ∴ a3 + b3 = (a + b)(a2 + b2 - ab) ]
p6 + q6 = (p2 + q2) × 0 = 0



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