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  1. If (2a – 1)2 + (4b – 3)2 + (4c + 5)2 = 0 ,then the value of
    a3 + b3 + c3 - 3abc
    = 0
    a2 + b2 + c2
    1. 1
      3
      8

    2. 2
      3
      8

    3. 3
      3
      8

    4. 0
Correct Option: D

(2a – 1)2 + (4b – 3)2 + (4c + 5)2 = 0

∴ 2a – 1 = 0 ⇒ 2a = 1 ⇒ a =
1
2

4b – 3 = 0 ⇒ 4b = 3 ⇒ b =
3
4

4c + 5 = 0 ⇒ 4c = –5 ⇒ c =
-5
4

[ If x2 + y2 + z2 = 0, x = 0, y = 0, z = 0]
∴ a + b + c =
1
+
3
-
5
244

a + b + c =
6 + 9 - 15
= 0
12

∴ a3 + b3 + c3 - 3abc = 0
∴ Required answer = 0



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