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If (2a – 1)2 + (4b – 3)2 + (4c + 5)2 = 0 ,then the value of a3 + b3 + c3 - 3abc = 0 a2 + b2 + c2
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1 3 8
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2 3 8
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3 3 8
- 0
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Correct Option: D
(2a – 1)2 + (4b – 3)2 + (4c + 5)2 = 0
∴ 2a – 1 = 0 ⇒ 2a = 1 ⇒ a = | ||
2 |
4b – 3 = 0 ⇒ 4b = 3 ⇒ b = | ||
4 |
4c + 5 = 0 ⇒ 4c = –5 ⇒ c = | ||
4 |
[ If x2 + y2 + z2 = 0, x = 0, y = 0, z = 0]
∴ a + b + c = | + | - | ||||
2 | 4 | 4 |
a + b + c = | = 0 | |
12 |
∴ a3 + b3 + c3 - 3abc = 0
∴ Required answer = 0