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  1. The value of x which satisfies the equation
    x + a2 + 2c2
    +
    x + b2 + 2a2
    +
    x + b2 + 2a2
    = 0 is
    b + cc + aa + b

    1. (a2 + b2 + c2)
    2. -(a2 + b2 + c2)
    3. (a2 + 2b2 + c2)
    4. -(a2 + b2 + 2c2)
Correct Option: B

Of the given options,
x = -(a2 + b2 + c2)

x + a2 + 2c2
=
- a2 - b2 - c2 + a2 + 2c2
b + cb + c

=
c2 - b2
= c – b
b + c

x + b2 + 2a2
=
- a2 - b2 - c2 + b2 + 2a2
c + ab + c

=
a2 - c2
= a – c
c + a

x + c2 + 2b2
=
- a2 - b2 - c2 + c2 + 2b2
a + bb + c

=
b2 - a2
= b – a
a + b

∴ c – b + a – c + b – a = 0



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