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  1. If 7sin2θ + 3cos2θ = 4 then the value of secθ + cosecθ is
    1. 2
      −2
      3
    2. 2
      + 2
      3
    3. 2
      3
    4. None of these
Correct Option: B

7sin2θ + 3cos2θ = 4
⇒  4 sin2θ + 3 sin2θ + 3 cos2θ = 4
⇒  4 sin2θ + 3(sin2θ + cos2θ) = 4
⇒  4 sin2θ = 4 – 3
[∵  sin2θ + cos2θ = 1]
⇒  4 sin2θ = 1

⇒  sin2θ =
1
4

⇒  sinθ =
1
= sin 30°
2

⇒  θ = 30°
∴  secθ + cosecθ
= sec 30° + cosec 30°
=
2
+ 2
3



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