If r sinθ = 1, r cosθ = √3 then the value

Home » Aptitude » Trigonometry » Question

r sinθ = 1 ..... (i)
r cosθ = √3 ..... (i)
On squaring and adding both equations,
r² sin²θ + r²cos²θ = 1 + 3
⇒ r² (sin²θ + cos²θ) = 4
⇒ r² = 4

Again, =	r sinθ	=	1
	r cosθ		√3

⇒ tanθ =	1
	√3

∴ r² tanθ =	4
	√3