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  1. (1 + sec 20° + cot 70°)(1 – cosec 20° + tan70°) is equal to
    1. 0
    2. 1
    3. 2
    4. 3
Correct Option: C

(1 + sec 20° + cot 70°) (1 – cosec 20° + tan 70°)
= (1 + sec 20° + tan 20°) (1 – cosec 20° + cot 20°)
[∴  tan (90° – θ) = cotθ; cot (90° – θ) = tanθ]

= 1 +
1
+
sin20°
1 −
1
+
cos20°
cos20°cos20°sin20°sin20°

=
cos20° + 1 + sin20°
sin20° – 1 + cos20°
cos20°sin20°

=
(sin20° + cos20° + 1)( sin20° + cos20° + 1)
sin20°.cos20°

=
(sin20° + cos20°)2 − 1
sin20°.cos20°

=
sin220° + cos220° + 2sin20°.cos20°− 1
sin20°.cos20°

=
1 + 2sin20°.cos20°− 1
= 2
sin20°.cos20°



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