- 
					 (1 + sec 20° + cot 70°)(1 – cosec 20° + tan70°) is equal to
- 
                        - 0
- 1
- 2
- 3
 
Correct Option: C
(1 + sec 20° + cot 70°) (1 – cosec 20° + tan 70°)
= (1 + sec 20° + tan 20°) (1 – cosec 20° + cot 20°)
[∴  tan (90° – θ) = cotθ; cot (90° – θ)  = tanθ]
| = |  | 1 + | + |  |  | 1 − | + |  | ||||
| cos20° | cos20° | sin20° | sin20° | 
| = |  |  |  |  | ||
| cos20° | sin20° | 
| = | |
| sin20°.cos20° | 
| = | |
| sin20°.cos20° | 
| = | |
| sin20°.cos20° | 
| = | = 2 | |
| sin20°.cos20° | 
 
	