a2 + b2 + c2 + 3 = 2a – 2b – 2c⇒ a2 – 2a + 1 + b2 + 2b + 1 + c2 + 2c + 1 = 0⇒ (a – 1)2 + (b + 1)2 + (c + 1)2 = 0∴ a – 1 = 0 ⇒ a = 1b + 1 = 0 ⇒ b = –1c + 1 = 0 ⇒ c = –1∴ 2a – b + c = 2 + 1 – 1 = 2
Previous Question Next Question
Your comments will be displayed only after manual approval.