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  1. If x = 1 + √2 + √3, then the value of (2x4 – 8x3 + 26x – 28) is
    1. 2√2
    2. 3√3
    3. 5√5
    4. 6√6
Correct Option: D

x = 1 + √2 + √3
⇒ x - 1 = √3 + √2
On squaring both sides ,
x2 – 2x + 1 = 3 + 2 + 2√6
⇒ x2 – 2x + 1 - 5 = 2√6
⇒ x2 – 2x - 4 = 2√6
On squaring again,
(x2 – 2x - 4)2 = (2√6)2
⇒ x4 + 4x2 + 16 – 4x3 + 16x - 8x2 = 24
⇒ x4 – 4x3 - 4x2 + 16x - 8x2 - 8 = 0
⇒ 2x4 – 8x3 - 8x2 + 32x - 16 = 0
∴ 2x4 – 8x3 - 5x2 + 32x - 16 + 3x2 - 6x - 12
= 0 + 3 (x2 – 2x – 4) = 3 × 2√6
Required answer = 6√6



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