8 men can do a work in 12 days. After 6 days of work, 4

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8 men can do a work in 12 days. After 6 days of work, 4 more men were engaged to finish the work. In how many days would the remaining work be completed?

Using Rule 1,
Work done by 8 men in 6 days

=	6	=	1
	12		2

Remaining work = 1 -	1	=	1
	2		2

4 more men are engaged.
∴ Total number of men
= 8 + 4 = 12
By work and time formula

	W₁	=	W₂	, we have
	M₁D₁		M₂D₂

	1	=	1/2
	8 × 12		12 × D₂

⇒ D₂ =	1	×	8 × 12	= 4 days
	2		12