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A, B and C together can do a piece of work in 40 days. After working with B and C for 16 days, A leaves and then B and C complete the remaining work in 40 days more. A alone could do the work in
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- 80 days
- 90 days
- 100 days
- 120 days
Correct Option: C
A, B and C together complete the work in 40 days.
∴ (A + B + C)’s 1 day’s work
= | 40 |
∴ (A + B + C)’s 16 days work
= | = | |||
40 | 5 |
Remaining work = 1 – | = | |||
5 | 5 |
This part of work is done by B and C in 40 days.
∴ Time taken in doing | work = 40 days. | 5 |
∴ Time taken in doing in 1 work
= | = | days | ||
3 | 3 |
∴ A’s day’s work = (A + B + C)’s 1 day’s work – (B + C)’s 1 day’s work
= | - | |||
40 | 200 |
= | = | = | ||||
200 | 200 | 100 |
∴ Required time = 100 days