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  1. A, B and C together can do a piece of work in 40 days. After working with B and C for 16 days, A leaves and then B and C complete the remaining work in 40 days more. A alone could do the work in
    1. 80 days
    2. 90 days
    3. 100 days
    4. 120 days
Correct Option: C

A, B and C together complete the work in 40 days.
∴ (A + B + C)’s 1 day’s work

=
1
40

∴ (A + B + C)’s 16 days work
=
16
=
2
405

Remaining work = 1 –
2
=
3
55

This part of work is done by B and C in 40 days.
∴ Time taken in doing
3
work = 40 days.
5

∴ Time taken in doing in 1 work
=
40 × 5
=
200
days
33

∴ A’s day’s work = (A + B + C)’s 1 day’s work – (B + C)’s 1 day’s work
=
1
-
3
40200

=
5 - 3
=
2
=
1
200200100

∴ Required time = 100 days



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