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A certain number of men complete a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. The number of men originally was
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- 30
- 40
- 32
- 36
Correct Option: B
Number of men originally = x (let)
∴ M1 D1 = M2 D2
⇒ x × 60 = (x + 8) × 50
⇒ 6x = 5x + 40
⇒ 6x – 5x = 40
⇒ x = 40 men
Aliter : Using Rule 23,
Here, D= 60, a = 8, d =10
| ∴ Required number= | d |
| = | = 40 | 10 |
