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A can do a piece of work in 10 days and B can do it in 12 days. They work together for 3 days. Then B leaves and A alone continues. 2 days after that C joins and the work is completed in 2 days more. In how many days can C do it, if he works alone ?
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- 30 days
- 50 days
- 40 days
- 60 days
Correct Option: C
Let C alone complete the work in x days.
According to the question, A’s 7 days’ work + B’s 3 days’ work + C’s 2 days’ work = 1
| ⇒ | + | + | = 1 | |||
| 10 | 12 | x |
| ⇒ | = 1 - | - | |||
| x | 10 | 4 |
| = | = | ||
| 20 | 20 |
⇒ x = 2 × 20 = 40 days
