-
6 men and 8 women can do a work in 10 days, Then 3 men and 4 women can do the same work in
-
- 24 days
- 20 days
- 12 days
- 18 days
Correct Option: B
6m + 8w ≡ 10 days
⇒ 2 (3m + 4w) ≡ 10 days
⇒ 3m + 4w ≡ 20 days
[Since the workforce has become half of the original force, so number of days must be double].
Aliter :
Using Rule 14,
Let us assume efficiency of 6 men
= efficiency of 8 men.
A = 6, a = 20
B = 8, b = 20
A1 = 3, B1 = 4
| ∴ Required time = | ||||
| + | ||||
| A × a | B × b | |||
| = | ||||
| + | ||||
| 40 | 40 | |||
| = | = 20days | |
| 2 |
