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A man does double the work done by a boy in the same time. The number of days that 3 men and 4 boys will take to finish a work which can be done by 10 men in 8 days is
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- 4
- 16
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7 3 11 -
8 4 days 5
Correct Option: B
According to the question,
1 man ≡ 2 boys
∴ 3 men + 4 boys ≡ (3 + 2) men ≡ 5 men
∴ M1D1 = M2D2
⇒ 5 × D1 = 10 × 8
| ⇒ D1 = | = 16 days | 5 |
