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A works twice as fast as B. If B can complete a piece of work independently in 12 days, then what will be the number of days taken by A and B together to finish the work?
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- 4
- 6
- 8
- 18
Correct Option: A
A is twice efficient than B.
∴ Time taken by B = 12 days
⇒ Time taken by A = 6 days
∴ (A + B)’s 1 day’s work
| = | + | = | = | |||||
| 6 | 12 | 12 | 4 |
∴ Required time = 4 days
