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  1. Evaluate :
    sec 39°
    +
    2
    (tan 17° . tan 38° . tan 60° . tan 52° . tan 73° – 3 (sin231° + sin259°)
    cosec 51°3

    1. 2
    2. 3
    3. 0
    4. –2
Correct Option: C

sec 39°
+
2
tan17°. tan38° . tan60° . cot (90° – 52°) . cot (90° – 73°) – 3 (sin²31° + cos²(90° – 59°)
sec(90° - 51°)3

=
sec 39°
+
2
tan17°. tan38° × √3 . cot 38° . cot 17° – 3 (sin²31° + cos² 31°)
sec 39°3

= 1 +
2
× √3(tan 17° . cot17°) .(tan 38° . cot38°) – 3 × 1 = 1 + 2 – 3 = 0
3

tanq . cotq = 1
tan (90° – θ) cotθ ;
cot (90° – θ) tanθ ;
sec (90° – θ) cosecθ



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