Correct Option: C

Here,

cosx = –	3	and p < x <	3π
	5		2

⇒ x lies in third quadrant, and we know that in third quadrant only tan and cot are positive.
Consider right angled ∆ABC,

Using pythagoras theorem,
AC² = AB² + BC²
⇒ 5² = (–3)² + BC²
16 = BC²
⇒ BC = 4
We know that,
sin2A = 2sinA × cosA
⇒ sin2x = 2 × sinx× cosx

= 2 ×		- 4		×	- 3
		5			5

=	24
	25

∵ Here, sinq is –ve