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					 If cosq = – 1/2 and θ lies in third quadrant, then what will be the value of sinθ + tanθ
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                        -  1 2 
 
-  2 √3 
-  √3 2 
-  1 √3 
 
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Correct Option: C
Here, cosθ = – 1/2 and θ, lies in third quadrant
Consider ∆ABC, 
Using Pythagoras theorem, 
AC² = AB² + BC² 
2² = (–1)² + BC² 
⇒ BC² = 4 – 1 
BC² = 3 
BC = √3
| tanθ + sinθ = – |  |  | + - |  |  | |||
| - 1 | 2 | 
∵ In third quadrant sinθ is negative and tanθ is positive.
=
| = | |
| 2 | 
 
	