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If cosq = – 1/2 and θ lies in third quadrant, then what will be the value of sinθ + tanθ
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1 2
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2 √3 -
√3 2 -
1 √3
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Correct Option: C
Here, cosθ = – 1/2 and θ, lies in third quadrant
Consider ∆ABC,
Using Pythagoras theorem,
AC² = AB² + BC²
2² = (–1)² + BC²
⇒ BC² = 4 – 1
BC² = 3
BC = √3
tanθ + sinθ = – | + - | |||||||
- 1 | 2 |
∵ In third quadrant sinθ is negative and tanθ is positive.
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2 |