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  1. If tanθ + cotθ = 2, then the value of (tannθ + cotnθ) is :
    1. 2n
    2. 2n/2
    3. 21/2
    4. 2
Correct Option: D

tanθ + cotθ = 2

⇒ tanθ +
1
 = 2
tanθ

⇒
tan²θ + 1
 = 2
tanθ

→ tan²θ + 1 = 2 tanθ
⇒ tan²θ – 2 tanθ + 1 = 0
⇒ (tanθ – 1)2 = 0
⇒ tanθ – 1 = 0
⇒ tanq = 1
∴ cotθ = 1
∴ tannθ + cotnθ = 1 + 1 = 2


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