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If tanq = 1, then the value of 8sinθ + 5cosθ is : sin²θ - 2cos²θ + 7cosθ
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- 1
- 3
- 2
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1 2
Correct Option: C
| Expression = | |
| sin³θ - 2cos³θ + 7cosθ |
Dividing numerator and denominator by cos³θ
| = | + | ||||
| cos³θ | cos³θ | ||||
| - | + | ||||
| cos³θ | cos³θ | cos³θ | |||
| = | |
| tan³θ - 2 + 7(1 + tan²θ) |
| = | |
| 1 - 2 + 7(1 + 1) |
| = | |
| 1 - 2 + 14 |
| = | = 2 | |
| 13 |
