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The value of the expression 2 (sin6θ + cos6θ) –3 (sin4θ + cos4θ) + 1 is
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- –1
- 0
- 1
- 2
Correct Option: B
2 (sin6θ + cos6θ) – 3 (sin4θ + cos4θ) + 1
= 2 {(sin²θ + cos²θ)3 –3 sin²q cos²θ (sin²θ + cos²θ)} – 3 {(sin²θ + cos²θ)2 – 2 sin²θ . cos²θ} + 1
= 2 (1 – 3 sin²θ . cos²θ) – 3 (1 – 2 sin²θ . cos²θ) + 1
= 2 – 6 sin²θ . cos²θ – 3 + 6 sin²θ . cos²θ + 1
= 3 – 3 = 0
