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The radius of the incircle of the equilateral triangle having each side 6 cm is
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- 2√3cm
- √3 cm
- 6√3 cm
- 2 cm
Correct Option: B
On the basis of given question , we draw a figure
E = In-centre, AD ⊥ BC
AB = 6 cm, BD = 3 cm
∠ ADB = 90°
∴ AD = √AB² - BD²
AD = √6² - 3²
AD = √36 - 9
AD = √27
AD = 3√3 cm
∴ In-radius = ( 1/3 ) AD
In-radius = | × 3√3 = √3cm | |
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