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					 Let ABC be an equilateral triangle and AD perpendicular to BC. Then AB² + BC² + CA² = ?
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                        -  2AD² 
 
-  3AD² 
 
-  4AD² 
 
- 5AD²
 
-  2AD² 
Correct Option: D
As per the given in question, we draw a figure of an equilateral triangle ABC  
 
Here , AD ⊥ BC 
∴ BD = DC = AB/2 = AC/2 = CB/2
Use the Pythagoras formula to get the length of AD. 
| AD = | AB = | BC = | AC | |||
| 2 | 2 | 2 | 
| ⇒ AB = | AD = BC = AC | |
| √3 | 
| ∴ AB² + BC² + AC² = |  | + | + |  | AD² = 4AD² | |||
| 3 | 3 | 3 | 
 
	