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Let ABC be an equilateral triangle and AD perpendicular to BC. Then AB² + BC² + CA² = ?
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- 2AD²
- 3AD²
- 4AD²
- 5AD²
- 2AD²
Correct Option: D
As per the given in question, we draw a figure of an equilateral triangle ABC
Here , AD ⊥ BC
∴ BD = DC = AB/2 = AC/2 = CB/2
Use the Pythagoras formula to get the length of AD.
AD = | AB = | BC = | AC | |||
2 | 2 | 2 |
⇒ AB = | AD = BC = AC | |
√3 |
∴ AB² + BC² + AC² = | + | + | AD² = 4AD² | |||||
3 | 3 | 3 |