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The centroid of an equilateral triangle ABC is G. If AB is 6 cms, the length of AG is
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- √3cm
- 2√3 cm
- 3√2 cm
- 2√2cm
- √3cm
Correct Option: B
We draw a figure of an equilateral triangle ABC whose G is centroid and side is 6 cm ,
AB = 6 cm.; AD ⊥ BC
∴ BD = DC = 3 cm.
In ∆ABD,
AD = √AB² – BD²
AD = √6² – 3²
AD = √36 - 9
AD = √27 = 3 √3 cm.
∴ AG = | AD = | × 3√3 | ||
3 | 3 |
AG = 2√3 cm.