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					 The centroid of an equilateral triangle ABC is G. If AB is 6 cms, the length of AG is
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                        -  √3cm 
 
-  2√3 cm 
 
-  3√2 cm 
 
- 2√2cm
 
-  √3cm 
Correct Option: B
We draw a figure of an equilateral triangle ABC whose G is centroid and side is 6 cm ,   
 
AB = 6 cm.; AD ⊥ BC
∴ BD = DC = 3 cm. 
In ∆ABD, 
AD = √AB² – BD²
AD = √6² – 3² 
AD = √36 - 9
AD = √27 = 3 √3 cm.
| ∴ AG = | AD = | × 3√3 | ||
| 3 | 3 | 
AG = 2√3 cm.
 
	