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In ∆ABC, BD and CE are perpendicular to AC and AB respectively. If BD = CE, then ∆ ABC is
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- Equilateral
- Isosceles
- Right–angled
- Scalene
- Equilateral
Correct Option: B
As per the given in question , we draw a figure of a triangle ABC in which BD and CE are perpendicular to AC and AB respectively , 
| Area of ∆ ABC = | × AB × CE | |
| 2 |
| Area of ∆ ABC = | × AC × BD | |
| 2 |
⇒ AB = AC [∵BD = CE]
∴ ∆ ABC is an isosceles triangle.
