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					 ∆ABC is an isosceles triangle with AB = AC = 10 cm, AD = 8 cm is the median on BC from A. The length of BC is
- 
                        -  8 cm 
 
-  12 cm 
 
-  10 cm 
 
- 6 cm
 
-  8 cm 
Correct Option: B
We draw a figure of an isosceles triangle ABC with AB = AC = 10 cm, AD = 8 cm is the median on BC from A ,
D, is the mid–point of BC. 
Given that , AB = AC = 10 cm. 
AD ⊥ BC 
From ∆ ABD, 
BD = √AB² - AD² 
BD = √10² - 8²
BD = √100 - 64 
BD = √36 = 6 cm. 
∴ BC = 2BD = 2 × 6 = 12 cm.
 
	