The external bisector of ∠B and ∠C of ∆ABC (where AB and AC extended to E and F respectively) meet at point P. If ∠BAC = 100°, then the measure of ∠BPC is
50°
80°
40°
100°
Correct Option: C
In &&8710;ABC ∠A = x, ∠B = y; ∠C = z In ∆PBC, ∠PBC + ∠PCB + ∠BPC = 180°
