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In a triangle ABC, AB + BC = 12 cm, BC + CA = 14 cm and CA + AB = 18 cm. Find the radius of the circle (in cm) which has the same perimeter as the triangle.
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5 2 -
7 2 -
9 2 -
11 2
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Correct Option: B
Given that , AB + BC = 12
BC + CA = 14
CA + AB = 18
On adding , we get
∴ 2(AB + BC + CA) = 12 + 14 + 18 = 44
⇒ AB + BC + CA = 22
∴ 2πr = 22
| ⇒ 2 × | × r = 22 | 7 |
| ⇒ r = | cm | |
| 2 |
