In a ∆ABC, if 2 ∠ A = 3 ∠ B = 6∠C, value

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As per the given in question,
∴ 2∠A = 3∠B = 6∠C

⇒	2∠A	=	3∠B	=	6∠C
	6		6		6

⇒	∠A	=	∠B	=	∠C
	3		2		1

⇒ ∠A : ∠B : ∠C = 3 : 2 : 1

∴ ∠B =		2		× 180°
		1 + 2 + 3

∠B =		2	× 180° = 60°
		6