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In ∆ ABC, AB = AC, O is a point on BC such that BO = CO and OD is perpendicular to AB and OE is perpendicular to AC. If ∠BOD = 30° then measure of ∠AOE is
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- 45°
- 60°
- 75°
- 30°
- 45°
Correct Option: B
As per the given in question , we draw a figure of triangle ABC
∠BDO = 90°
∠BOD = 30°
∴ ∠DBO = 60°
∠B = ∠C = 60°
∴ ∠EOC = 30°
AO is bisector of BC.
∴ ∠DOE = 120°
∴ ∠AOE = ∠AOD = 60°