Home » Aptitude » Plane Geometry » Question
  1. In ∆ ABC, AB = AC, O is a point on BC such that BO = CO and OD is perpendicular to AB and OE is perpendicular to AC. If ∠BOD = 30° then measure of ∠AOE is
    1. 45°
    2. 60°
    3. 75°
    4. 30°
Correct Option: B

As per the given in question , we draw a figure of triangle ABC

∠BDO = 90°
∠BOD = 30°
∴ ∠DBO = 60°
∠B = ∠C = 60°
∴ ∠EOC = 30°
AO is bisector of BC.
∴ ∠DOE = 120°
∴ ∠AOE = ∠AOD = 60°



Your comments will be displayed only after manual approval.