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In ∆ ABC, D and E are two mid points of sides AB and AC respectively. If ∠BAC = 40° and ∠ABC = 65° then ∠CED is :
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- 130°
- 75°
- 125°
- 105°
- 130°
Correct Option: D
Firstly , We draw a figure of triangle ABC in which D and E are two mid points of sides AB and AC respectively.
Here , ∠BAC = 40°, ∠ABC = 65°
∴ ∠ACB = 180° – ∠BAC - ∠ABC = 180° - 40° – 65° = 75°
DE || BC
∴ ∠AED = ∠ACB = 75°
∴ ∠CED = 180° – 75° = 105°