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					 In a triangle ABC, if ∠A + ∠C = 140° and ∠A + ∠B = 180°, then ∠A is equal to
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                        -  80° 
 
-  40° 
 
-  60° 
 
- 20°
 
-  80° 
Correct Option: C
Given that , ∠A + ∠C = 140° and ∠A + ∠B = 180°
In a ∆ ABC, 
We know that , ∠A + ∠B + ∠C = 180° 
⇒ ∠B + 140° = 180° 
⇒ ∠B = 180° – 140° = 40°
∴ ∠A + 3 ∠B = 180° 
⇒ ∠A + 3 × 40° = 180° 
⇒ ∠A = 180° – 120° = 60°.
 
	