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B1 is a point on the side AC of ∆ABC and B1B is joined. A line is drawn through A parallel to B1B meeting BC at A1 and another line is drawn through C parallel to B1B meeting AB produced at C1. Then
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1 - 1 = 1 CC1 AA1 BB1 -
1 + 1 = 1 CC1 AA1 BB1 -
1 + 1 = 2 BB1 AA1 CC1 -
1 + 1 = 2 AA1 CC1 BB1
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Correct Option: B
According to question , we draw a figure
In ∆ AA1C and ∆BB1C,
BB1 || AA1 ⇒ ∆AA1C ~ ∆BB1C
∴ | = | ..... (i) | ||
BB1 | B1C |
In ∆ ACC1 and ∆ ABB1,
BB1 || CC1 ⇒ ∆ACC1 ~ ∆ABB1
∴ | = | ||
BB1 | AB1 |
⇒ | = | = | |||
CC1 | AC | AC |
⇒ | = 1 - | ||
CC1 | AC |
⇒ | = 1 - | [From equation (i) | ||
CC1 | AA1 |
⇒ | + | = 1 | ||
CC1 | AA1 |
⇒ | + | = | |||
CC1 | AA1 | BB1 |