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  1. B1 is a point on the side AC of ∆ABC and B1B is joined. A line is drawn through A parallel to B1B meeting BC at A1 and another line is drawn through C parallel to B1B meeting AB produced at C1. Then
    1. 1
      -
      1
      =
      1
      CC1AA1BB1
    2. 1
      +
      1
      =
      1
      CC1AA1BB1
    3. 1
      +
      1
      =
      2
      BB1AA1CC1
    4. 1
      +
      1
      =
      2
      AA1CC1BB1
Correct Option: B

According to question , we draw a figure

In ∆ AA1C and ∆BB1C,
BB1 || AA1 ⇒ ∆AA1C ~ ∆BB1C

AA1
=
AC
..... (i)
BB1B1C

In ∆ ACC1 and ∆ ABB1,
BB1 || CC1 ⇒ ∆ACC1 ~ ∆ABB1
CC1
=
AC
BB1AB1

BB1
=
AB1
=
AC - B1C
CC1ACAC

BB1
= 1 -
B1C
CC1AC

BB1
= 1 -
BB1
[From equation (i)
CC1AA1

BB1
+
BB1
= 1
CC1AA1

1
+
1
=
1
CC1AA1BB1



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