Incentre of ∆ ABC is I. ∠ABC = 90° and ∠ACB

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Incentre of ∆ ABC is I. ∠ABC = 90° and ∠ACB = 70°. ∠AIC is

1. 115°
2. 100°
3. 110°
4. 105°
5. None of these

Correct Option: E

As per the given in question , we draw a figure triangle ABC whose I is incentre ,

The point of intersection of internal bisectors of the angles of a triangle is incentre.
Given that , ∠ABC = 90° and ∠ACB = 70°
As we know that , ∠BAC + ∠ABC + ∠ACB = 180°
∠BAC = 180° – 90° – 70° = 20°

∴ ∠AIC = 180 -	∠A	-	∠C
	2		2

∠AIC = 180° –10° – 35° = 135°