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In ∆ ABC, ∠B = 70° and ∠C = 60°. The internal bisectors of the two smallest angles of ∆ ABC meet at O. The angle so formed at O is
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- 125°
- 120°
- 115°
- 110°
- 125°
Correct Option: A
We draw a figure triangle ABC in which the internal bisectors of the two smallest angles of ∆ ABC meet at O ,
Given , ∠B = 70° ; ∠C = 60°
We know that , ∠A + ∠B + ∠C = 180°
∴ ∠A = 180° – 70° – 60° = 50°
According to the question,
∠OAC = 25° ;
∠OCA = 30°
∴ ∠AOC = 180° – 25° – 30° = 125°