In ∆ ABC if the median ( 1/2 ) AD = BC, then ∠BAC

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According to question , we draw a figure ∆ ABC

Point ‘D’ is the mid-point of side BC.

AD =	1	BC
	2

⇒ 2AD = BC
∴ AD = BD = DC
∴ AB = AC
∴ AD ⊥ BC
∴ ∠ABD = ∠DAB = 45°
∴ ∠BAC = 90°