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In ∆ ABC, AC = BC and ∠ABC = 50°, the side BC is produced to D so that BC = CD then the value of ∠BAD is
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- 80°
- 40°
- 90°
- 50°
- 80°
Correct Option: C
We draw a figure triangle ABC whose the side BC is produced to D so that BC = CD ,
Given , AC = BC and ∠ABC = ∠BAC = 50°
∴ ∠ACB = 180° – 100° = 80°
∴ ∠ACD = 180° – 80° = 100
∠CAD = ∠CDA = | = 40° | |
2 |
∴ ∠BAD = ∠BAC + ∠CAD
∠BAD = 50° + 40° = 90°