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In a triangle ABC, OB and OC are the bisectors of angles ∠B and ∠C respectively. ∠BAC = 60°. The angle ∠BOC will be :
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- 150°
- 120°
- 100°
- 90°
- 150°
Correct Option: B
On the basis of question we draw a figure of triangle ABC in which OB and OC are the bisectors of angles ∠B and ∠C respectively , 
In ∆ABC,
Given , ∠BAC = 60°
∴ ∠ABC + ∠ACB = 180° – 60° = 120°
| ⇒ | (∠ABC + ∠ACB) = 60° | |
| 2 |
In ∆BOC,
⇒ ∠OBC + ∠OCB + ∠BOC = 180°
| ⇒ | (∠ABC + ∠ACB) + ∠BOC = 180° | |
| 2 |
⇒ ∠BOC = 180° – 60° = 120°
