-
In ∆ ABC, the height CD intersects AB at D. The mid-points of AB and BC are P and Q respectively. If AD = 8 cm and CD = 6 cm, then the length of PQ is
-
- 3 cm
- 7 cm
- 9 cm
- 5 cm
- 3 cm
Correct Option: D
On the basis of question we draw a figure of triangle ABC ,
From ∆ ACD,
Given , AD = 8 cm.
CD = 6 cm.
∠CDA = 90°
∴ AC = √AD² + DC²
AC = √8² + 6²
AC = √64 + 36
AC = √100 = 10 cm
The straight line joining the midpoints of two sides of a triangle is parallel to the third side and half of third side.
∴ PQ = | AC = | = 5cm. | ||
2 | 2 |