- 
					 In ∆ ABC, the height CD intersects AB at D. The mid-points of AB and BC are P and Q respectively. If AD = 8 cm and CD = 6 cm, then the length of PQ is
- 
                        -   3 cm 
 
-  7 cm 
 
-   9 cm 
 
- 5 cm
 
-   3 cm 
Correct Option: D
On the basis of question we draw a figure of triangle ABC ,  
From ∆ ACD, 
Given , AD = 8 cm. 
CD = 6 cm. 
∠CDA = 90° 
∴ AC = √AD² + DC² 
AC = √8² + 6²
AC = √64 + 36
AC = √100 = 10 cm 
The straight line joining the midpoints of two sides of a triangle is parallel to the third side and half of third side.
| ∴ PQ = | AC = | = 5cm. | ||
| 2 | 2 | 
 
	