In ∆ ABC, ∠B = 35°, ∠C = 65° and the bisector

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In ∆ ABC, ∠B = 35°, ∠C = 65° and the bisector of ∠BAC meets BC in D. Then ∠ADB is :

1. 40°
2. 75°
3. 90°
4. 105°

Correct Option: D

According to question , we draw a figure ∆ ABC

Given , ∠ABC = 35°
∠ACB = 65°
∴ ∠BAC + ∠ABC + ∠ACB = 180°
∠BAC = 180° – 35° – 65°
∠BAC = 180° – 100° = 80°
∠BAD = ∠DAC = 40°
∴ ∠ADB = 180° – 35° – 40° = 105°