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In a ∆ ABC, D and E are points on AC and BC respectively, AB and DE are perpendicular to BC. If AB = 9 cm , DE = 3 cm and AC = 24 cm, then AD is :
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- 32cm
- 16cm
- 8 cm
- 4 cm
- 32cm
Correct Option: B
According to question , we draw a figure triangle ABC
In ∆ ABC and ∆ DEC
AB || DE
Given that , AB = 9 cm , DE = 3 cm and AC = 24 cm
∴ ∠ABC = ∠DEC = 90°
∠CAB = ∠CDE
By AA-similarity theorem,
∆ ABC ~ ∆DEC
∴ | = | ||
DE | CD |
⇒ | = | ||
3 | CD |
⇒ 3 = | ||
CD |
⇒ CD = | = 8 cm. | |
3 |
∴ AD = AC – CD = 24 – 8 = 16 cm