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					 ABC is a right-angled triangle with AB = 6 cm and BC = 8 cm. A circle with centre O has been inscribed inside ∆ABC. The radius of the circle is
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                        -  1 cm 
 
-  2 cm 
 
-  3 cm 
 
- 4 cm
 
-  1 cm 
Correct Option: B
As per the given in question , we draw a figure right-angled triangle ABC in which inscribed inside a circle with centre O ,
AC = √AB² + BC²
AC = √6² +  8²
AC = √36 + 64 
AC = √100 = 10 cm 
OD = OE = OF = radii = r cm 
∴ Area of [∆ AOB + ∆ BOC + ∆ AOC] = ∆ABC
| ⇒ | × 6 × r + | × 8 × r + | × 10 × r = | × 8 × 6 | ||||
| 2 | 2 | 2 | 2 | 
⇒ 3r + 4r + 5r = 24
⇒ 12r = 24
| ⇒ r = | = 12 cm. | |
| 2 | 
 
	