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ABC is a right-angled triangle with AB = 6 cm and BC = 8 cm. A circle with centre O has been inscribed inside ∆ABC. The radius of the circle is
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- 1 cm
- 2 cm
- 3 cm
- 4 cm
- 1 cm
Correct Option: B
As per the given in question , we draw a figure right-angled triangle ABC in which inscribed inside a circle with centre O ,
AC = √AB² + BC²
AC = √6² + 8²
AC = √36 + 64
AC = √100 = 10 cm
OD = OE = OF = radii = r cm
∴ Area of [∆ AOB + ∆ BOC + ∆ AOC] = ∆ABC
⇒ | × 6 × r + | × 8 × r + | × 10 × r = | × 8 × 6 | ||||
2 | 2 | 2 | 2 |
⇒ 3r + 4r + 5r = 24
⇒ 12r = 24
⇒ r = | = 12 cm. | |
2 |